Final answer:
If a 71 kg man did not lose any heat during chin-ups, his temperature would increase by approximately 0.4°C.
Step-by-step explanation:
To calculate the amount by which the temperature of a 71 kg man would increase if he did not lose any heat during chin-ups, we need to first calculate the total amount of energy produced during the chin-ups. The energy produced can be calculated by multiplying the number of chin-ups (20) by the energy produced per kg of body mass (0.115 kcal per kg).
This gives us
(20 * 0.115 kcal/kg) = 2.3 kcal.
1 kcal is equal to 4184 joules, so the energy produced is
(2.3 * 4184 J) = 9611.2 J.
To find the temperature increase, we can use the specific heat capacity formula:
Q = mcΔT,
where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
In this case, the heat energy Q is 9611.2 J, the mass m is 71 kg, and the specific heat capacity c for the human body is approximately 3500 J/kg·°C.
Rearranging the formula, we can solve for ΔT:
ΔT = Q / (mc)
= 9611.2 J / (71 kg * 3500 J/kg·°C)
≈ 0.4 °C.
Therefore, if the participant did not lose any heat, his temperature would increase by approximately 0.4°C during the chin-ups.