The number of positive zeros of the polynomial f(x) = 4x⁹ + 5x⁸ + 4x⁶ + 9x + 1 is 3
How to determine the number of positive zeros that the polynomial function may have.
From the question, we have the following parameters that can be used in our computation:
f(x) = 4x⁹ + 5x⁸ + 4x⁶ + 9x + 1
Differentiate the function
So, we have
f'(x) = 36x⁸ + 40x⁷ + 24x⁵ + 9
There are 4 positive signs in the above
This means that the number of positive zeros of the polynomial is 4 - 1.
Hence, the number of positive zeros of the polynomial is 3