Question

Please answer (i’ll include more points)

Answer 1

The domain f(t) is {30, 40, 50, 60}.

The range f(t) is {40, 50, 60, 70}.

The domain of
`f^-1`(t) is {40, 50, 60, 70}.

The range of
`f^-1`(t) is {30, 40, 50, 60}.

`f^-1`(60) = 50.

How to find domain and range

Based on the given function values:

t: 30, 40, 50, 60

f(t): 40, 50, 60, 70

The domain of f(t) refers to the set of all possible input values for the function. In this case, the domain is {30, 40, 50, 60}.

The range of f(t) refers to the set of all possible output values for the function.

In this case, the range is {40, 50, 60, 70}.

To find the inverse function, we need to switch the roles of t and f(t) and solve for t:

t: 40, 50, 60, 70

`f^-1`(t): 30, 40, 50, 60

The domain of
`f^-1`(t) is the set of all possible input values for the inverse function. In this case, the domain is {40, 50, 60, 70}.

The range of
`f^-1`(t) is the set of all possible output values for the inverse function. In this case, the range is {30, 40, 50, 60}.

To find
`f^-1`(60), we look for the input value that corresponds to the output value of 60 in the original function:

f(t) = 60

t: 30, 40, 50, 60

f(t): 40, 50, 60, 70

From the given values, we can see that f(50) = 60. Therefore,
`f^-1`(60) = 50.