Question

A solution was prepared by mixing benzene (C6H6) and carbon tetrachloride (CC14). Given that the mole fraction of carbon tetrachloride is 0.820 in the solution obtained from 2.69 mol CC14, calculate the moles of benzene used.

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Answer 1

The moles of benzene used in the solution are 0.4852 mol.

Step-by-step explanation:

To calculate the moles of benzene used in the solution, we can use the mole fraction and the moles of carbon tetrachloride.

Mole fraction is calculated by dividing the moles of one component by the total moles of all components.

Given that the mole fraction of carbon tetrachloride is 0.820 and we have 2.69 mol of carbon tetrachloride, we can use this information to find the moles of benzene.

We can start by calculating the moles of carbon tetrachloride using the equation:

moles of CC14 = mole fraction of CC14 * total moles of all components

Substituting the given values, we get:

moles of CC14 = 0.820 * 2.69 mol = 2.2048 mol

Since benzene and carbon tetrachloride are the only components, the moles of benzene will be equal to the total moles of all components minus the moles of carbon tetrachloride:

moles of benzene = total moles of all components - moles of CC14

Substituting the values, we get:

moles of benzene = 2.69 mol - 2.2048 mol = 0.4852 mol

Therefore, the moles of benzene used in the solution are 0.4852 mol.