190k views
0 votes
Critical values for quick reference during this activity.

Confidence level Critical value
523330.3825238.qx3zqy7
In a poll of
randomly selected voters in a local election,
voters were against fire department bond measures.

What is the sample proportion
?

What is the margin of error
for the
confidence level?
Ex: 0.123

User Sirish V
by
8.9k points

1 Answer

1 vote

The Sample proportion is 0.728

The Margin of error is given as 0.0276

How to get the sample proportion

Sample proportion

= 728 / 1000

= 0.728

The margin of error

1 - α/2

= 0.975

The critical value = 1.96

Margin of error =


1.96*\sqrt{(0.728(1-0.728))/(1000) }

= 0.0276

The Margin of error is given as 0.0276

question

Critical values for quick reference during this activity.

Confidence level Critical value

0.90 z∗=1.645

0.95 z∗=1.960

0.99 z∗=2.576

Jump to level 1

In a poll of 1000 randomly selected voters in a local election, 728 voters were against school bond measures. What is the sample proportion p^? (Should be a decimal answer)

What is the margin of error m for the 95% confidence level?

User Emreturka
by
7.9k points