Final answer:
The total momentum of the system, with each of three particles having an individual momentum of 100 kg·m/s in the +x direction, is 300 kg·m/s.
Step-by-step explanation:
The question concerns the total momentum of a system composed of three particles, each with an individual momentum of 100 kg·m/s, moving in the +x direction. Since momentum is a vector quantity and all particles are moving in the same direction, their momenta can be simply added together to find the total momentum of the system. Therefore, the total momentum of the system will be the sum of the individual momenta, which can be calculated as:
Total Momentum = Momentum of Particle 1 + Momentum of Particle 2 + Momentum of Particle 3
Total Momentum = 100 kg·m/s + 100 kg·m/s + 100 kg·m/s
Total Momentum = 300 kg·m/s
The total momentum of the system is 300 kg·m/s in the +x direction. In this context, we assume that there is no net external force acting on the system (Fnet = 0) and thus conservation of momentum applies.