Question

0.5 points

In order to be accepted into a certain top university, applicants must score within the top 7% nationally on the SAT exam. The exam has a mean of 1000, a
deviation of 200 and the scores are normally distributed. What is the lowest possible score a student can have and still qualify for acceptance into the university

Answer 1

To find the lowest possible score a student can have and still qualify for acceptance into a top university, we need to calculate the z-score for the top 7% and then use the z-score to find the corresponding score.

Step-by-step explanation:

To find the lowest possible score a student can have and still qualify for acceptance into the university, we need to determine the cutoff score for the top 7% nationally. In order to do this, we will use the z-score formula:

z = (x - mean) / deviation

First, calculate the z-score corresponding to the top 7% by using the formula:

z = InvNorm(1 - 0.07)

Substitute the values into the formula:

z = InvNorm(0.93) ≈ 1.48

Next, use the z-score formula to find the corresponding score:

x = mean + (z * deviation)

Substitute the values into the formula:

x = 1000 + (1.48 * 200) ≈ 1296

Therefore, the lowest possible score a student can have and still qualify for acceptance into the university is approximately 1296.