L) The submarine is 115.3 m away from surface of water it is 500 m away from the starting point.
M) The height of the flagpole is 23.8 m .
The missing sides are:
a) 15. 56 cm b) 12√2 mm c) 16√3/3 m.
How the missing sides were calculated.
L) The submarine dived at angle 13⁰
tan13 = x/500
x = 500tan13
= 500 * 0.2309
= 115.3 m
The submarine is 115.3 m away from surface of water it is 500 m away from the starting point.
M) The height = x
tan50 = x/20
x = 20tan50
x = 23.8 m
The height of the flagpole is 23.8 m .
2a) cos50 = adjacent/hypotenuse
cos50 = 10/x
x = 10/cos50
= 10/0.6428
=15. 56 cm
b) sin45 = 12/x
x = 12/sin45
x = 12/(1/√2) = 12 *√2/1
x = 12√2 mm
c) sin60 = 8/x
x = 8/sin60
x = 8/(√3/2) = 8 * 2/√3
= 16/√3
= 16√3/3 m.