The concentration of the HF solution is obtained as 0.000034 M.
What is neutralization reaction?
Volume of base used in trial 1 = 12.36 mL - 1.94 mL
10.42 mL
Volume of base used in trial 2 = 21.01 mL - 10.32 mL
= 10.70 mL
Volume of base used in trial 3 = 29.73 mL - 18.97 mL
= 10.76 mL
Average volume of base = 10.42 + 10.70 + 10.76 /3
= 10.63 mL
Moles of sodium hydroxide = 0.316 M * 10.63/1000 L
= 0.0034 moles
The equation of the reaction is;
Since the reaction is 1:1
Concentration of the HF = 0.0034 moles * 10/1000 L
= 0.000034 M