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Water is run through a hydraulic turbine at a rate of 11,500 L/min from a 160-m-high reservoir and produces 250 kW of shaft power. What is the efficiency of this turbine?
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Water is run through a hydraulic turbine at a rate of 11,500 L/min from a 160-m-high reservoir and produces 250 kW of shaft power. What is the efficiency of this turbine?

User Numan Tariq
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1 Answer

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Step-by-step explanation:

11500 Liters/min = 191.667 liter per second ( 191.667 kg/sec)

at 160 meters this represents

potential energy = m g h

191.667 (9.81)(160) = 300 840 J

since this is PER SECOND, it is also 300 840 Watts

SO efficiency is then

250 000 watts out / ( 300 840 watts in) * 100% = 83.1 %

User JesseDyer
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