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Help ppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Help ppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp-example-1

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Answer:

To construct triangle ABC given the information:

1. Draw a line segment AB of length 8 cm.

2. Use a protractor to draw angle BAC of 40° at point A.

3. Use a protractor to draw angle ABC of 50° at point B, making sure it intersects line AB.

After constructing the triangle, to find the length of side BC, you can use the Law of Sines:


\(\frac{{BC}}{{\sin A}} = \frac{{AB}}{{\sin C}}\)

Here, A is angle BAC (40°), B is angle ABC (50°), and AB is the length of side AB (8 cm).

First, find angle C using the fact that the sum of angles in a triangle is 180°:


\(C = 180° - A - B = 180° - 40° - 50° = 90°\)

Now apply the Law of Sines:


\(\frac{{BC}}{{\sin 40°}} = \frac{{8 \text{ cm}}}{{\sin 90°}}\)


\(\frac{{BC}}{{\sin 40°}} = \frac{8}{{1}}\)


\(BC = \frac{8}{{\sin 40°}}\)

Using a calculator to find the value of
\(BC\):


\(BC ≈ \frac{8}{{\sin 40°}} ≈ (8)/(0.6428) ≈ 12.448\) cm

Therefore, the length of side BC is approximately 12.4 cm (rounded to 1 decimal place).

Explanation:

User Muhfred
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