Question

HELP! Please answer in steps so I can repeat what you did on my own and actually learn something, thanks so much in advance. :D

Answer 1

The value that can be used to clear the fractions is 6.

How to determine the values that can be used to clear the fractions?

The value that can be used to clear the fractions must be lowest common multiple (LCM) of the denominator of the fractions.

The given faction equation;

`(7)/(2) x \ - \ (1)/(3) = 5`

The denominator of the fractions is given as 2 and 3; the LCM of the fractions is calculated as follows;

LCM of 2 and 3 = 2 x 3 = 6

We will multiply through the equation with 6 in order to clear the fraction.

`6 ((7)/(2) x) \ - \ ( (1)/(3))6 = 5(6)\\\\3(7x) - 2(1) = 30\\\\21x - 2 = 30\\\\21x = 32\\\\x = (32)/(21)`

Thus, the value that can be used to clear the fractions is 6.