Question

PLEASE HELP IN UNDER 7 MINS

Answer 1

`\sf\\3a.\ \textsf{Here, triangles ADE and ABC are congruent by SAS axiom.}\\\textsf{In triangle ABC,}\\i.\ \angle C=90^o-\angle A\ \ \ [\textsf{Acute angles of right triangle are complementary.}]\\or,\ \angle C=90^o-57^o\\or,\ \angle C=33^o\\ii.\ \angle C=\angle DAE=33^o\ \ \ [\textsf{Corresponding angles of congruent triangles are equal.}]\\iii.\ \angle BAC=\angle E\ \ \ [\textsf{Corresponding angles of congruent triangles are equal.}]`

`\sf\\b.\ Solution:\\1.\ m\angle D=30^o\ \ \ [\textsf{Corresponding angles of congruent triangles are equal.}]\\2.\ CD=7cm\ \ \ [\textsf{Corresponding sides of congruent triangles are equal.}]\\3.\ \angle ACD+\angle D+\angle DAC=180^o\ \ \ [\textsf{Sum of angles of triangle is }180^o.]\\or,\ \angle ACD+30^o+25^o=180^o\\or,\ \angle ACD=125^o`