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Solve 2x ^ 2 + 5x - 3 > 0

1 Answer

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Final answer:

By factoring the quadratic equation and analyzing the intervals on a number line, we can determine the solution to be (-3, 1/2).

Step-by-step explanation:

To solve the inequality 2x^2 + 5x - 3 > 0, we can find the roots of the corresponding quadratic equation 2x^2 + 5x - 3 = 0.

Since the coefficient of x^2 is positive, the parabola opens upwards and we need to find the values of x that make the quadratic expression positive.

We can do this by finding the x-intercepts of the quadratic equation and determining the intervals for which the expression is greater than zero.

  1. First, let's factor the quadratic equation. We have (2x - 1)(x + 3) = 0.
  2. Setting each factor equal to zero, we get 2x - 1 = 0 and x + 3 = 0.
  3. Solving for x, we find x = 1/2 and x = -3.
  4. Plotting these two x-values on a number line, we have:
  • In the region x < -3, the expression 2x^2 + 5x - 3 is negative.
  • In the region -3 < x < 1/2, the expression is positive.
  • In the region x > 1/2, the expression is also negative.

Therefore, the intervals for which the inequality 2x^2 + 5x - 3 > 0 are: (-3, 1/2).

User Egor Margineanu
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