The graph of the Ionization energy of 3p, 4p, and 5p subshells is shown in the image attached.
Ionization energy of 3p, 4p, and 5p subshells
Subshells 3p, 4p, and 5p exhibit a predictable trend in their ionization energy. Over time, the ionization energy of an atom usually increases as its electrons are removed.
Because it is closest to the nucleus, the 3p subshell in particular has the lowest ionization energy. The 5p subshell, which is situated further away from the nucleus, has the highest ionization energy, followed by the 4p subshell, which has a higher ionization energy. This trend is a result of electrons in these subshells experiencing less electron shielding and an increase in effective nuclear charge.