Final answer:
The total cost of painting the inner four walls of a rectangular water tank is 480 rupees, based on a rate of 100 rupees per 3 square meters. For the water consumption, since the tank holds 7200 liters, and the rate is 50 paise per liter, one family would pay 1800 rupees for a full tank assuming equal sharing.
Step-by-step explanation:
The question asks for two separate calculations related to a rectangular water tank used by two families.
Part A:
The cost of painting the inner four walls of the tank is requested. The surface area to be painted is the sum of the areas of the four walls. Since two opposite walls are identical, we can calculate the area of one pair and then double it.
For the front and back walls (3 m x 1.6 m each), the area is:
- 2 walls x (3 m x 1.6 m) = 9.6 square meters.
For the side walls (1.5 m x 1.6 m each), the area is:
- 2 walls x (1.5 m x 1.6 m) = 4.8 square meters.
Total area to be painted is:
- 9.6 m² + 4.8 m² = 14.4 m².
At a rate of 100 rupees per 3 square meters, the total cost is calculated by:
- Total cost = (14.4 m² / 3 m²) x 100 rupees = 480 rupees.
Part B:
For the water consumption cost, first we must find the volume of the tank to determine how much water it holds and thus how much one family will pay. The volume of the tank is:
- Volume = length x width x height = 3 m x 1.5 m x 1.6 m = 7.2 cubic meters.
Since there are 1000 liters in one cubic meter, the tank holds 7200 liters of water. At a rate of 50 paise per liter, the total cost for the full tank is:
- Total cost = 7200 liters x 0.50 rupees/liter = 3600 rupees.
Since both families pay equally, the amount one family will have to pay is:
- One family's cost = Total cost / 2 = 3600 rupees / 2 = 1800 rupees.