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An object is placed 10cm from a diverging lens of a focal length 60 cm. Determine the nature and size of the image



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Step-by-step explanation:

Determining the size of the image

We can use the lens formula to calculate the image distance and magnification:

1/f = 1/u + 1/v

where:

f is the focal length of the lens (60 cm in this case)

u is the object distance (10 cm)

v is the image distance

Plugging in the values, we get:

1/60 = 1/10 + 1/v

Solving for v, we get:

v = -15 cm

The negative sign indicates that the image is virtual, as we already know.

Now, we can use the magnification formula:

M = v/u

where:

M is the magnification

v is the image distance

u is the object distance

Plugging in the values, we get:

M = -15 cm / 10 cm = -1.5

The negative magnification indicates that the image is inverted, which is consistent with the fact that it is a virtual image. The absolute value of the magnification tells us that the image is smaller than the object by a factor of 1.5.

Therefore, the image is virtual, upright, diminished, and 1.5 times smaller than the object.

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