Question

120cm3 of ethane were mixed with 140 cm3 of oxygen and the mixture exploded to complete reaction. Calculate the volume of the resulting gaseous mixture

when measured at room temperature and pressure.

Answer 1

To calculate the volume of the resulting gaseous mixture, we need to determine the limiting reactant in the reaction and use the stoichiometry of the balanced equation. We can compare the number of moles of each reactant using the ideal gas law equation and then find the volume of the resulting gaseous mixture.

Step-by-step explanation:

To calculate the volume of the resulting gaseous mixture, we need to first determine the limiting reactant in the reaction. The balanced equation for the reaction is:

2 CH3CH3 (g) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (g)

We have 120 cm3 of ethane and 140 cm3 of oxygen. To find the limiting reactant, we can compare the number of moles of each reactant. The number of moles can be calculated using the ideal gas law equation:

n = PV / RT

where n is the number of moles, P is the pressure, V is the volume, R is the ideal gas constant, and T is the temperature. Since both reactants are measured at the same conditions of temperature and pressure, we can compare their moles directly. Once we determine the limiting reactant, we can calculate the volume of the resulting gaseous mixture by using the stoichiometry of the balanced equation.