Final answer:
To calculate the volume in milliliters of a 1.74M nickel(ll) chloride solution containing 200g of NiCl2, you need to convert grams to moles and use the formula Volume (L) = moles (mol) / Molarity (M). The volume is 888 mL.
Step-by-step explanation:
To calculate the volume in milliliters of the 1.74M nickel(ll) chloride solution that contains 200g of nickel (ll) chloride (NiCl2), we need to use the formula:
Molarity (M) = moles (mol) / Volume (L)
First, we need to convert grams to moles by dividing the mass by the molar mass of NiCl2. The molar mass of NiCl2 = 129.61 g/mol. So, moles of NiCl2 = 200 g / 129.61 g/mol = 1.544 mol.
Next, we can rearrange the formula to solve for Volume (L):
Volume (L) = moles (mol) / Molarity (M) = 1.544 mol / 1.74 M = 0.888 L.
Finally, we convert the volume from liters to milliliters:
Volume (mL) = 0.888 L * 1000 mL/L = 888 mL.