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Each door is 0.850 m wide. Sound of frequency 652 Hz is coming through the entrance from within the room. The speed of sound is 343 m/s. What is the diffraction angle of the sound under each of the following situations? when it passes through the doorway when one door is open. when it passes through the doorway when both doors are open

User Rousseauo
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Final answer:

The diffraction angle of sound can be determined using the equation sin(θ) = λ / w, where λ is the wavelength and w is the doorway width. With a frequency of 652 Hz and a speed of sound of 343 m/s, the wavelength is approximately 0.526 m. The diffraction angles are found using the arcsin function for the doorway width of 0.850 m when one door is open, and 1.700 m when both doors are open.

Step-by-step explanation:

To determine the diffraction angle of sound passing through a doorway, we can use the equation for the first minimum of a single-slit diffraction pattern, which is sin(θ) = λ / w, where θ is the diffraction angle, λ is the wavelength of sound, and w is the width of the slit (in this case, the doorway).

First, we need to calculate the wavelength (λ) of the sound wave using the formula λ = c / f, where c is the speed of sound and f is the frequency. Given that the speed of sound c is 343 m/s and the frequency f is 652 Hz for the sound coming through the room, the wavelength is:

λ = 343 m/s / 652 Hz = approximately 0.526 m.

When one door is open (0.850 m wide), the diffraction angle θ for the first minimum can be found as follows:

sin(θ) = λ / w = 0.526 m / 0.850 m

∴ θ = arcsin(0.526 m / 0.850 m).

Similarly, when both doors are open (1.700 m wide), the diffraction angle θ is computed in the same manner:

sin(θ) = λ / w = 0.526 m / 1.700 m

∴ θ = arcsin(0.526 m / 1.700 m).

To get the actual angles in degrees, one would need to use a calculator to compute the arcsin values.

User LebRon
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