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Evaluate the integral integrate x ^ 2 * e ^ x dx

User MuSTaNG
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1 Answer

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The integral is ∫x²eˣ dx = x² eˣ - 2xeˣ + 2eˣ + C

How to integrate using part integration.

Let's use integration by parts. The integration by parts formula is given by:

∫udv = uv - ∫vdu

Let's choose u = x² and dv = eˣd

du = 2xdx

v = ∫eˣ dx = eˣ

Now, apply the integration by parts formula:

∫x² eˣdx = x² eˣ - ∫2x eˣ dx

∫x² eˣdx = x² eˣ - ∫2x eˣdx

Let u = 2x and dv = eˣdx then calculate du and v.

du = 2dx

v = ∫eˣdx = eˣ

Apply the integration by parts formula again:

∫2x eˣdx = 2xeˣ - ∫2eˣdx

∫2eˣ dx = 2eˣ

∫x² eˣ dx = x² eˣ - (2xeˣ - 2eˣ)

Combine like terms:

∫x²eˣ dx = x² eˣ - 2xeˣ + 2eˣ + C

where C is the constant of integration.

User Wsn
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