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The boiling point of amphetamine, C9H13N, is 201.0°C at 760.0 torr and 83.0°C at 13.0 torr. What is the concentration (in g/m3) of amphetamine when it is in contact with 20.0°C air

User Roshith
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Final answer:

To determine the concentration of amphetamine in contact with 20.0°C air, we can use the Clausius-Clapeyron equation to find the vapor pressure and convert it to concentration.

Step-by-step explanation:

To determine the concentration of amphetamine in contact with 20.0°C air, we need to calculate the vapor pressure of amphetamine at 20.0°C using the given boiling point data at different pressures.

Using the Clausius-Clapeyron equation, we can express the relationship between vapor pressure and temperature:

P1/P2 = exp[(ΔHvap/R)(1/T2 - 1/T1)]

Using the data provided, we can substitute the boiling points and pressure values to solve for ΔHvap:

201.0°C --> 760.0 torr
83.0°C --> 13.0 torr

Plugging in the values into the equation and rearranging to solve for ΔHvap:

ΔHvap = (R x ln(P2/P1))/(1/T2 - 1/T1)

where R is the ideal gas constant and ln is the natural logarithm.

Once we have ΔHvap, we can use it to calculate the vapor pressure of amphetamine at 20.0°C. Then, using the ideal gas equation, we can convert the vapor pressure to concentration in g/m³.

User Dhiren
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