Question

A gas is found to have a pressure of 700 torr at a

temperature of 54°C. If the volume of the gas under
T₁=327K
these conditions is 3.31 ft, what was the original
volume when the temperature was 20°C and pressure
was 700 terr?
T₂=293

Answer 1

The original volume when the temperature was 20°C and the pressure was 700 torr was approximately 3.08 ft³.

Step-by-step explanation:

To solve this problem, we can use the combined gas law formula:

P₁V₁/T₁ = P₂V₂/T₂

We are given:

• P₁ = 700 torr
• T₁ = 54°C = 327K
• V₁ = 3.31 ft³
• T₂ = 20°C = 293K
• P₂ = 700 torr (constant pressure)

By substituting these values into the formula, we can solve for V₂:

700 torr * 3.31 ft³ / 327K = 700 torr * V₂ / 293K

V₂ = (700 torr * 3.31 ft³ * 293K) / (327K * 700 torr) = 3.08 ft³

The original volume when the temperature was 20°C and the pressure was 700 torr was approximately 3.08 ft³.