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8. _____ atoms of Xe = 67.8 L at STP
9. _____g H₂O = 112 L of H₂O at STP

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There are approximately 1.83 x
10^2^4 atoms of Xe in 67.8 L at STP.

112 L of H₂O at STP is approximately equal to 90.075 grams.

How to find mass of water

To answer these questions, se the concept of molar volume at standard temperature and pressure (STP).

At STP, 1 mole of any gas occupies a volume of 22.4 liters. Using this information, calculate the number of moles or grams for the given volumes:

To find the number of atoms of Xe, determine the number of moles using the molar volume of 22.4 liters/mol at STP.

We can set up the following proportion:

1 mol Xe / 22.4 L = x mol Xe / 67.8 L

Cross-multiplying and solving for x:

x = (1 mol Xe / 22.4 L) * 67.8 L

x ≈ 3.03 mol Xe

To calculate the number of atoms, multiply the number of moles by Avogadro's number, which is approximately 6.022 x
10^2^3 atoms/mol:

Number of atoms = 3.03 mol Xe * (6.022 x 10^23 atoms/mol)

Number of atoms ≈ 1.83 x
10^2^4 atoms

Therefore, there are approximately 1.83 x
10^2^4 atoms of Xe in 67.8 L at STP.

To find the mass of H₂O, determine the number of moles using the molar volume of 22.4 liters/mol at STP. We can set up the following proportion:

1 mol H₂O / 22.4 L = x mol H₂O / 112 L

Cross-multiplying and solving for x:

x = (1 mol H₂O / 22.4 L) * 112 L

x ≈ 5 mol H₂O

The molar mass of water (H₂O) is approximately 18.015 g/mol. To calculate the mass of H₂O, multiply the number of moles by the molar mass:

Mass of H₂O = 5 mol H₂O * 18.015 g/mol

Mass of H₂O ≈ 90.075 g

Therefore, 112 L of H₂O at STP is approximately equal to 90.075 grams.

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