Question

If 0.475 g Mg reacts with 116.75 mL of 1.08 M HCl, how many mol of H2 gas will be produced?

Mg(s)+2HCl(aq) --> MgCl2(aq)+H2(g)

Answer 1

To determine the number of moles of H2 gas produced, we can use the stoichiometric coefficients from the balanced equation. Given the mass of Mg and the volume and concentration of HCl, we can calculate the number of moles of each reactant and then determine the moles of H2 gas produced based on the stoichiometry.

Step-by-step explanation:

To determine the number of moles of H2 gas produced, we can use the stoichiometric coefficients from the balanced equation.

From the balanced equation: 1 mol of Mg reacts with 2 mol of HCl to produce 1 mol of H2 gas.

Given that 0.475 g of Mg and 116.75 mL of 1.08 M HCl are reacted, we need to convert the volume of HCl to moles. Since the concentration is given in Molarity (mol/L), we can use the equation:

moles = concentration x volume (in L)

moles of HCl = 1.08 M x 116.75 mL / 1000 mL/L = 0.1245 mol

Based on the stoichiometry, when 0.475 g of Mg reacts with 0.1245 mol of HCl, 0.1245 mol of H2 gas will be produced.