Final answer:
To keep the pole motionless in a horizontal position, you need to exert a force equal to the weight of the pole as well as the torque created by the weight of the pole and its length. The force required is 22.87 N.
Step-by-step explanation:
To keep the pole motionless in a horizontal position, you need to exert a force equal to the weight of the pole as well as the torque created by the weight of the pole and its length.
The weight of the pole can be calculated using the formula
F = mg,
where F is the weight, m is the mass, and g is the acceleration due to gravity. In this case, the weight of the pole is
24 kg * 9.8 m/s² = 235.2 N.
The torque created by the weight of the pole can be calculated using the formula
Torque = force * distance.
The distance in this case is 35 cm = 0.35 m.
Therefore, the torque is
235.2 N * 0.35 m = 82.32 Nm.
To keep the pole motionless, you need to balance the torque created by the weight of the pole with an equal and opposite torque. This can be achieved by exerting a force at the end of the pole. The force required can be calculated using the formula Force = torque / distance. In this case, the distance is 3.6 m.
Therefore, the force required is 82.32 Nm / 3.6 m = 22.87 N.