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Find a polynomial function whose graph passes through ​(​7,11​), ​(11​,-10​), and ​(0​,3​)

User Avitenberg
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1 Answer

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Final answer:

The polynomial function whose graph passes through ​(​7,11​), ​(11​,-10​), and ​(0​,3​) is x^3 - 18x^2 + 77x - 77.

Step-by-step explanation:

To find a polynomial function that passes through the given points (7,11), (11,-10), and (0,3), we can use the fact that when a polynomial function passes through a point (x,y), the equation of the function can be written as:

(x-a)(x-b)(x-c)... = 0, where a, b, c, etc. are the x-coordinates of the given points.

So, for the given points, the polynomial function can be written as (x-7)(x-11)(x-0) = 0.

Expanding this equation, we get:

x^3 - 18x^2 + 77x - 77 = 0.

Therefore, the polynomial function is f(x) = x^3 - 18x^2 + 77x - 77.

User Pernell
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