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Calculate the vapor pressure lowering of a solution of 2.00g of aspirin (M=180.15 g/mol) in 50.0g of methanol (M=32.042g/mol) at 21.2°C. Methanol has a vapor pressure of 101 torr at this temperature.

User Sogrady
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Final answer:

To calculate the vapor pressure lowering of a solution, we can use Raoult's Law. First, calculate the mole fraction of methanol. Then, use Raoult's Law to calculate the vapor pressure lowering. Finally, subtract the vapor pressure lowering from the vapor pressure of the pure solvent to obtain the vapor pressure above the resulting solution.

Step-by-step explanation:

To calculate the vapor pressure lowering of a solution, we can use Raoult's Law, which states that the vapor pressure of a solvent above a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution. The change in vapor pressure is then calculated by subtracting the vapor pressure of the solution from the vapor pressure of the pure solvent.

In this case, we have 2.00g of aspirin and 50.0g of methanol. First, we need to calculate the mole fraction of methanol using the equation:

Mole Fraction of Methanol = Moles of Methanol / Total Moles

Next, we can use Raoult's Law to calculate the vapor pressure lowering:

Vapor Pressure Lowering = Vapor Pressure of Methanol × Mole Fraction of Methanol

Finally, we subtract the vapor pressure lowering from the vapor pressure of the pure solvent to obtain the vapor pressure above the resulting solution.

User Egvo
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