Final answer:
The equation of the line that contains the points (-2, -2) and (4, 10) is y = 2x + 2, which is derived by calculating the slope and using one of the points in the point-slope form.
Step-by-step explanation:
To find the equation of the line that contains the points (-2, -2) and (4, 10), we need to calculate the slope of the line and then use one of the points to find the equation using point-slope form. We start by calculating the slope using the formula (y2 - y1)/(x2 - x1). Substituting the values, we get (10 - (-2))/(4 - (-2)) = 12/6 = 2. With a slope of 2, we can now apply this to the point-slope equation y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Using the point (-2, -2), we get y - (-2) = 2(x - (-2)), which simplifies to y + 2 = 2x + 4. To write it in a standard linear form, we subtract 2 from both sides to get y = 2x + 2. This is the equation of the line that contains the points (-2, -2) and (4, 10).