Final answer:
The number of grams of O2 gas that can be stored in a compressed gas cylinder with a volume of 40 L, filled at 150 atm and 21°C, is 613.76 grams.
Step-by-step explanation:
The number of grams of O2 gas that can be stored in a compressed gas cylinder with a volume of 40 L can be calculated using the ideal gas law equation, PV = nRT.
Given that the cylinder is filled at 150 atm and 21°C, we can rearrange the equation to solve for the number of moles of O2, n. From there, we can convert moles to grams using the molar mass of O2.
First, let's convert 21°C to Kelvin:
21 + 273 = 294 K.
Next, we can use the equation PV = nRT to solve for n:
n = PV / RT
Substituting the given values:
n = (150 atm) * (40 L) / [(0.0821 L * atm / (mol * K)) * 294 K]
Calculating n gives us:
n = 19.18 moles
To convert moles to grams, we multiply the number of moles by the molar mass of O2:
grams of O2 = moles of O2 * molar mass of O2
Using the molar mass of O2, which is 32 g/mol, we have:
grams of O2 = 19.18 moles * 32 g/mol = 613.76 grams