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A cat, walking along the window ledge of a New York apartment, knocks off a flower pot, which falls to the street 200 feet below. How fast is the flower pot traveling when it hits the street? (Give your answer in ft/sec and in mph, given that .)

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The flower pot is traveling at approximately 113.3 ft/sec or 77.27 mph when it hits the street.

To determine the speed at which the flower pot is traveling when it hits the street, we can use the principles of physics and the equations of motion. Assuming there is no air resistance, we can analyze the situation using the equation for free-fall motion.

The equation for free-fall motion is:

h = (1/2) * g * t^2

where h is the height, g is the acceleration due to gravity (approximately 32 ft/sec^2), and t is the time.

Given that the flower pot falls from a height of 200 feet, we can rearrange the equation to solve for time:

200 = (1/2) * 32 * t^2

Simplifying the equation, we have:

t^2 = 200/16

t^2 = 12.5

Taking the square root of both sides, we find:

t = √12.5

t ≈ 3.54 seconds

Now that we have the time it takes for the flower pot to fall, we can find its speed using the equation:

v = g * t

v = 32 * 3.54

v ≈ 113.3 ft/sec

To convert this speed to mph, we can multiply by the conversion factor:

mph = ft/sec * 0.6818

mph ≈ 113.3 * 0.6818

mph ≈ 77.27 mph

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