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P(x)= x^4- 4x^3- x^2+ 4x

Its zeros are X1=___,X2=___,X3=___,X4=___, with X1<_ X2<_ X3<_ X4<_

1 Answer

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The roots of the equation p(x) = x⁴- 4x³- x² + 4x is

x1 = -1

x2 = 0

x3 = 1

x4 = 4

How to find the roots

The roots of a polynomial is the value of the x variables of the polynomial when the equation is set to zero.

Graphically, this roots of the equation are points where the equation intercepts the x-axis.

In the graph, these points are

A (-1, 0)

B (0, 0)

C (1, 0)

D (4, 0)

P(x)= x^4- 4x^3- x^2+ 4x Its zeros are X1=___,X2=___,X3=___,X4=___, with X1<_ X-example-1
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