Question

A fly accumulates 6.2 x 10-10 C of positive charge as it flies through the air. What is the magnitude of the electric field at a location 4.3 cm away from the fly? Express your answer to the nearest whole number.

Answer 1

The magnitude of the electric field at a location 4.3 cm away from the fly is approximately 247000 N/C.

Step-by-step explanation:

The magnitude of the electric field at a location 4.3 cm away from the fly can be calculated using the formula for electric field:

E = k * Q / r^2

Where E is the electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the charge of the fly (6.2 x 10^-10 C), and r is the distance from the fly (4.3 cm = 0.043 m).

Plugging in the values, we get:
E = (8.99 x 10^9 N m^2/C^2) * (6.2 x 10^-10 C) / (0.043 m)^2

Calculating this expression gives us the electric field magnitude, which is approximately 2.47 x 10^5 N/C.

Rounding this to the nearest whole number gives us 247000 N/C.