Question

Sasha solved a division problem by subtracting and keeping track as shown. Identify the problem that was solved. 492 minus 450 = 42. 42 minus 30 = 12. 15 times 30 = 450. 15 times 2 = 30. 32 remainder 12. 492÷32 492÷15 492÷12 492÷44

Answer 1

Sasha was solving the division problem 492 ÷ 15, which resulted in 32 with a remainder of 12 after performing sequential subtractions and tracking the results.

Step-by-step explanation:

Sasha solved a division problem by repeatedly subtracting multiples of the divisor from the dividend and tracking the results. Based on the provided subtractions and multiplications, Sasha was solving the division problem 492 ÷ 15. Here's an explanation of the steps involved:

• 492 minus 450 = 42 shows subtracting 15 times 30 (which is 450) from 492.
• 42 minus 30 = 12 indicates subtracting another 15 times 2 (which is 30) from the remainder 42.
• The combined multiplication facts of 15 times 30 = 450 and 15 times 2 = 30 align with these subtractions.
• Adding these multiples of 15 (30 + 2), we find that Sasha subtracted 32 units of 15 from 492, leaving a remainder of 12, thus solving for 492 ÷ 15 = 32 remainder 12.