The diver's final velocity before hitting the water is approximately 23.0 m/s. The total time of flight for the jump is around 2.35 seconds. These calculations assume that air resistance is negligible.
Step-by-step explanation:
To calculate the final velocity of a cliff diver jumping from a height of 27 meters, we can use the kinematic equation for uniformly accelerated motion without an initial velocity:
v = √(2gh), where g is the acceleration due to gravity (9.8 m/s²) and h is the height (27 meters).
Plugging in the values, we get: v = √(2 * 9.8 m/s² * 27 m) = √(529.2 m²/s²) ≈ 23.0 m/s.
To determine the total time of flight, we use the time equation of free fall:
t = √(2h/g)
t = √(2 * 27 m / 9.8 m/s²) ≈ 2.35 seconds.
Thus, the diver's final velocity just before hitting the water is approximately 23.0 m/s, and the total time of flight is around 2.35 seconds.
The probable question can be:
"In Acapulco, Mexico, cliff divers perform breathtaking jumps from considerable heights into the ocean. If a cliff diver jumps from a platform that is 27 meters above the water's surface, calculate the diver's final velocity just before hitting the water, considering the acceleration due to gravity is approximately 9.8 m/s². Assume air resistance is negligible. Additionally, determine the total time of flight for the diver during the jump."