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A guided missile is propelled from the origin of a coordinate system with the x-axis along the ground and the y-axis vertical. Its path, or trajectory, is given by the equation

y = 464x − 16x2.
Find the object's maximum height.

User SArifin
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Final answer:

To find the maximum height of the missile's trajectory given by y = 464x - 16x^2, calculate the vertex of the parabola which occurs at x = 14.5. Substituting this x value into the equation gives a maximum height of y = 233 meters.

Step-by-step explanation:

The student has asked how to find the maximum height of a guided missile's trajectory described by the parabolic equation y = 464x − 16x2. To find this, we need to determine the apex of the parabola, which is where the derivative of the equation with respect to x equals zero (the point where the vertical velocity is zero). This occurs at the vertex of the parabola.

Taking the derivative of the function and setting it to zero:

  • dy/dx = 464 - 32x = 0
  • x = 464 / 32
  • x = 14.5

Substituting this value back into the original equation:

  • y = 464(14.5) - 16(14.5)2
  • y = 6728 - 3344
  • y = 233 m

This means the object's maximum height is 233 meters.

User Karthik Sunil
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