175k views
3 votes
Write an equation for the line in slope intercept form

Write an equation for the line in slope intercept form-example-1
User Sergeyol
by
7.6k points

1 Answer

5 votes

The equation of the line passing through the points (-1,6) and (3,-2) in slope-intercept form is y = -2x + 4.

By using the graph we can identify the two points are (-1,6) and (3,-2)

To write the equation of a line in slope-intercept form, we need two pieces of information: the slope of the line and the y-intercept.

The points (-1,6) and (3,-2), we can find the slope using the formula:

slope = (change in y) / (change in x)

Substituting the coordinates of the two points:

slope = (-2 - 6) / (3 - (-1))

= -8 / 4

= -2

Now that we have the slope, we can use the point-slope form of the equation:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope.

Using the point (-1,6) and the slope -2:

y - 6 = -2(x - (-1))

y - 6 = -2(x + 1)

y - 6 = -2x - 2

y = -2x + 4

Therefore, the equation of the line passing through the points (-1,6) and (3,-2) in slope-intercept form is y = -2x + 4.

User OShadmon
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories