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a sled with no initial velocity accelerates at a rate of 1.1 m/s^2 down the hill. how long does it take the sled to go 13 m to the bottom

User Rochelle C
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1 Answer

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Final answer:

The sled takes approximately 3.77 seconds to go 13 m down the hill. To find out how long it takes the sled to go 13 meters down the hill with an initial acceleration of 1.1 m/s2, we can use the kinematic equation that relates distance (s), acceleration (a), and time (t):

Step-by-step explanation:

To find the time it takes for the sled to go 13 m down the hill, we can use the kinematic equation:

d = v0t + 0.5at2

Here, d = 13 m (distance), v0 = 0 m/s (initial velocity), and a = 1.1 m/s2 (acceleration).

Plugging in these values, we get:

13 = 0 x t + 0.5 x 1.1 x t2

Simplifying the equation gives us a quadratic equation:

0.55t2 = 13

Solving for t gives us:

t = √(13/0.55)

Calculating t, we find that it takes approximately 3.77 seconds for the sled to go 13 m down the hill.

It takes approximately 4.86 seconds for the sled with an acceleration of 1.1 m/s^2 to travel 13 meters down the hill.

To find out how long it takes the sled to go 13 meters down the hill with an initial acceleration of 1.1 m/s2, we can use the kinematic equation that relates distance (s), acceleration (a), and time (t):

s = ½ a t2

We know the distance (s) is 13 meters, and the acceleration (a) is 1.1 m/s2. Using this information, we can solve for the time (t):

13 = ½ * 1.1 * t2

This simplifies to:

13 = 0.55 * t2

Dividing both sides by 0.55 gives:

t2 = 13 / 0.55

t2 = 23.6364

Finally, taking the square root of both sides gives:

t = √23.6364

t ≈ 4.86 seconds

Therefore, it takes approximately 4.86 seconds for the sled to travel 13 meters down the hill.

User Astasiak
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