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As balloon has a pressure of 1.10 atm and a volume of 755 ml. If the balloon has the pressure increased to 125 KPa, what is the new volume?

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Final answer:

Using Boyle's Law, the new volume of the balloon when the pressure is increased from 1.10 atm to 125 KPa is found to be 673.20 ml.

Step-by-step explanation:

The question involves the concept of gas laws from chemistry, specifically Boyle's Law, which states that for a given mass of gas at constant temperature, the volume of the gas is inversely proportional to its pressure.

Given that a balloon has a pressure of 1.10 atm and a volume of 755 ml, we are asked to find the new volume when the pressure is increased to 125 KPa.

First, it's important to convert all units to match, since 1 atm is equivalent to 101.325 KPa, the initial pressure is equivalent to 111.4575 KPa.

Using Boyle's Law (P1V1 = P2V2), we can solve for the new volume (V2).

Apply Boyle's Law: (111.4575 KPa)(755 ml) = (125 KPa)(V2).

Calculate for V2: V2 = (111.4575 KPa * 755 ml) / 125 KPa

= 673.20 ml.

Therefore, the new volume of the balloon when the pressure is increased to 125 KPa would be 673.20 ml.

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