Question

A soap bubble has an index of refraction of 1.33. what minimum thickness of this bubble will ensure maximum reflectance of normally incident 530 nm wavelength light? group of answer choices

A. 99.6 nm
B. 199 nm
C. 56.7 nm
D. 24.9 nm
E. 398 nm

Answer 1

The minimum thickness of the soap bubble to ensure maximum reflectance of normally incident 530 nm wavelength light is 199 nm.

Step-by-step explanation:

The reflectance of light at the interface between two media can be maximized when the thickness of the medium is equal to a multiple of half the wavelength of the incident light.

The formula for the minimum thickness to ensure maximum reflectance is given by:

1. d = (m + 1/2) * λ / (2 * n)

Where d is the minimum thickness, m is an integer representing the order of interference, λ is the wavelength of light, and n is the refractive index of the medium.

In the given question, the refractive index of the soap bubble is 1.33 and the wavelength of the light is 530 nm. Plugging these values into the formula

1. d = (m + 1/2) * 530 nm / (2 * 1.33)

Simplifying the equation, we get:

1. d = (m + 1/2) * 199 nm

By analyzing the options, we can see that the minimum thickness that will ensure maximum reflectance is 199 nm, which corresponds to option B.