Question

Consider a computer system where integers are defined by 32 bits, and bools are defined by 1 bit.

Let there be a page table composed of 5 rows, where each row is made up of five integers and six bools. How many bits are required to store this table?

Answer 1

To store a page table with 5 rows composed of five integers and six bools, 830 bits are required. This is calculated by summing up the bits for integers and bools for one row and then multiplying by the number of rows.

Step-by-step explanation:

The question involves determining the number of bits required to store a page table in a computer system where such a table consists of 5 rows, with each row made up of five integers and six bools. In this system, integers are defined by 32 bits each, and bools are defined by 1 bit each.

To calculate the total number of bits needed, we first calculate the number of bits used by the integers and bools in one row and then multiply that by the number of rows:

• Bits required for integers in one row = 5 integers * 32 bits each = 160 bits
• Bits required for bools in one row = 6 bools * 1 bit each = 6 bits
• Total bits in one row = 160 bits for integers + 6 bits for bools = 166 bits
• Total bits in the table = 166 bits per row * 5 rows = 830 bits

Therefore, the page table will require 830 bits of storage space.