Question

A cycle receives 44.8 kj by heat transfer from a hot reservoir at 157 c and rejects 33.3 kj by heat transfer to a cold reservoir at 47 c. is the cycle operating with approximately maximum possible efficiency?

(a) no
(b) yes 0%

Answer 1

To determine if the cycle is operating with approximately maximum possible efficiency, we need to calculate the efficiency of the cycle, which is 25.54%.

Step-by-step explanation:

To determine whether the cycle is operating with approximately maximum possible efficiency, we need to calculate the efficiency of the cycle.

The efficiency of a cyclic heat engine is given by the formula:

Efficiency = 1 - (Qc / Qh)

where Qc is the heat transferred to the cold reservoir and Qh is the heat transferred from the hot reservoir.

In this case, Qc is 33.3 kJ and Qh is 44.8 kJ. Plugging these values into the formula, we get:

Efficiency = 1 - (33.3 / 44.8) = 0.2554

So, the efficiency of the cycle is approximately 0.2554 or 25.54%.

Since the maximum possible efficiency for a heat engine operating between two temperatures is given by the Carnot Efficiency, which is determined by the temperatures of the hot and cold reservoirs, we cannot determine the maximum possible efficiency without knowing these temperatures. Therefore, we cannot determine whether the cycle is operating with approximately maximum possible efficiency.