Question

carbon monoxide is a toxic gas. if a container that holds 0.625mol of carbon monoxide with a volume of 14.0l was later found with a volume of 8.01l at the same pressure and temperature, how many moles of carbon monoxide must have escaped from the container?

Answer 1

0.275 mol of carbon monoxide escaped from the container. This was calculated using the molar volume ratio (Avogadro's Law) which states that at constant temperature and pressure, equal volumes of gases contain the same number of moles, given the initial and final volumes of the gas.

Step-by-step explanation:

The student's question revolves around the principles of gas laws, particularly Avogadro's Law, which states that at constant temperature and pressure, equal volumes of gases contain the same number of moles. Given that carbon monoxide (CO) is a toxic gas, when a container with 14.0L volume containing 0.625mol of CO is found later to have a volume of 8.01L under the same conditions, we're asked to calculate how many moles of CO have escaped.

To determine the number of moles that escaped, we can compare the initial and final conditions using the molar volume ratio:

• Initial Volume/Initial Moles = Final Volume/Final Moles

Therefore, solving for Final Moles (moles remaining in the container) we get:

Final Moles = (Initial Moles × Final Volume) / Initial Volume

Final Moles = (0.625 mol × 8.01 L) / 14.0 L = 0.35 mol

Now subtract the moles remaining from the initial moles to find moles escaped:

Moles Escaped = Initial Moles - Final Moles = 0.625 mol - 0.35 mol = 0.275 mol

So, 0.275 mol of carbon monoxide must have escaped from the container.