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A building is cube-shaped. It uses 16 access points, which are, on average, 10 meters apart from one another. The company wishes to reduced this to 8 meters. About how many 5 GHz access points would the company need for the building?

User Matphy
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Final answer:

To determine the number of 5 GHz access points needed for a building changing spacing from 10 meters to 8 meters, the inverse square of the ratio of distances is used, resulting in approximately 25 access points for full coverage.

Step-by-step explanation:

The question involves determining the number of 5 GHz access points needed if the distance between them is reduced from 10 meters to 8 meters. Given that the building is cube-shaped and currently uses 16 access points, we can assume that these access points are placed to cover the volume of the building uniformly. When the distance between access points is decreased to 8 meters, the coverage area for each access point becomes smaller, thus necessitating more access points for full coverage.

To approximate the number of additional access points needed, we can use the inverse square of the ratio of the current distance to the desired distance, because the signal coverage area essentially relates to the square of the distance (area = π * distance²). So, (⅖/⅛)² = (⅚/⅞)² = 1.56 times more access points are approximately needed. If 16 is currently sufficient, then 16 * 1.56 = approximately 25 access points would be required for 8 meters apart.

User Chiborg
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