Question

A sinusoidal transverse wave travels along a long, stretched string. the amplitude of this wave is 0.0919 m, its frequencyis 2.15 hz, and its wavelength is 1.67 m.

what is the shortest transverse distance d between a maximum and a minimum of the wave?

Answer 1

The shortest transverse distance between a maximum and a minimum of the wave is 0.835 meters.

Step-by-step explanation:

The shortest transverse distance, d, between a maximum and a minimum of the wave can be found by using the formula:

d = λ/2

where λ is the wavelength of the wave.

In this case, the wavelength is given as 1.67 m. Plugging this value into the formula, we have:

d = 1.67 m / 2 = 0.835 m

Therefore, the shortest transverse distance between a maximum and a minimum of the wave is 0.835 meters.