215k views
3 votes
A class measured the velocity over time of a rolling ball relative to the surface it traveled on.

velocity of ball

time(s) velocity (m/s)
0 0
1 0.5
2 1.0
3 1.5
4 2.0
5 2.5

if the same acceleration were maintained over time, what velocity would the ball have relative to the surface it traveled on after 15 s?

User Danation
by
7.6k points

1 Answer

3 votes

Final answer:

To determine the velocity of the ball after 15 seconds, you can use the constant acceleration calculated from the data points provided. The ball accelerates at 0.5 m/s², leading to a final velocity of 7.5 m/s after 15 seconds.

Step-by-step explanation:

The student is asking about the velocity of a rolling ball after 15 seconds given a constant acceleration.

Since the table provided indicates a constant increase in velocity of 0.5 m/s every second, we can use this to find the velocity after 15 seconds.

The initial velocity is 0 m/s, and after 1 second it's 0.5 m/s, after 2 seconds it's 1 m/s, and so on. This pattern shows a linear increase, which implies a constant acceleration.

Assuming the acceleration is constant, at time t seconds, the velocity v in m/s can be calculated as v = at, with a being constant acceleration.

To calculate the acceleration, we can use any of the given velocity-time data points.

For example, at t = 1 second, v = 0.5 m/s, so a = v/t = 0.5 m/s².

Using this acceleration, the velocity after 15 seconds is v = a * t = 0.5 m/s² * 15 s = 7.5 m/s.

Therefore, the velocity of the ball relative to the surface it traveled on after 15 seconds would be 7.5 m/s, assuming the same acceleration is maintained over time.

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories