Final answer:
The velocity of the puck after the force has been applied is 10.8125 m/s in the +x direction.
Step-by-step explanation:
To find the velocity of the puck after the force has been applied, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, we have F = 25 N and m = 0.16 kg. As the force is applied for 0.05 s, we can also use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. The initial velocity u is given as 3 m/s to the right.
Rearranging the equation, we get v = u + at, where v = ?, u = 3 m/s, a = F/m, and t = 0.05 s. Plugging in the values, we have v = 3 + (25/0.16)(0.05) = 3 + 7.8125 = 10.8125 m/s. So the velocity of the puck after the force has been applied is 10.8125 m/s to the right. Therefore, the correct answer is a. +x direction.