Final answer:
The probability of selecting a ticket divisible by 2 or 3 or 5 is 0.7 or 70%.
Step-by-step explanation:
To find the probability that the number drawn is divisible by 2 or 3 or 5, we need to determine the total number of tickets that are divisible by 2 or 3 or 5 and divide it by the total number of tickets. Let's calculate:
The number of tickets divisible by 2: There are 200/2 = 100 tickets.
The number of tickets divisible by 3: There are 200/3 = 66 tickets.
The number of tickets divisible by 5: There are 200/5 = 40 tickets.
However, we have counted some tickets twice as they are divisible by multiple numbers. To correct this, we need to find the numbers that are divisible by both 2 and 3, both 3 and 5, and both 2 and 5.
The number of tickets divisible by both 2 and 3: There are 200/6 = 33 tickets.
The number of tickets divisible by both 3 and 5: There are 200/15 = 13 tickets.
The number of tickets divisible by both 2 and 5: There are 200/10 = 20 tickets.
The number of tickets divisible by 2, 3, or 5: 100 + 66 + 40 - 33 - 13 - 20 = 140.
The probability of selecting a ticket divisible by 2 or 3 or 5: 140/200 = 0.7 or 70%.