Question

A and B can do a work in 20 days. When A works at 60% capacity, B has to work at 150% capacity to finish the work. Find in how many days the faster one will finish the work alone.

(a) 15 days
(b) 25 days
(c) 30 days
(d) 40 days

Answer 1

A can finish the work alone in (d) 40 days.

Step-by-step explanation:

To solve this problem, let's first assume that A can finish the work alone in x days. This means that in one day, A can complete 1/x of the work. We're given that when A works at 60% capacity, B has to work at 150% capacity to finish the work. This means that B's work rate is 1.5 times A's work rate.

Based on this information, we can set up the following equation:

(1/x) + (1.5/x) = 1/20

Simplifying the equation, we get:

2.5/x = 1/20

Solving for x, we find that x = 40. This means that A can finish the work alone in 40 days, so the answer is (d) 40 days.