Final answer:
The correct structure of the organic compound containing bromine is determined by calculating the moles of bromine, the molar mass of the compound, and comparing it with the structures provided. The nearest molar mass to the calculated value indicates the correct structure, which is (b) CH₂Br₂.
Step-by-step explanation:
The question provided pertains to the determination of the correct structure of an organic compound containing bromine, given that 0.172 g of this compound contains 0.08 g of bromine. To identify the correct structure, we need to calculate the approximate molar mass of bromine in the compound based on the data given and compare it with the molar mass of the options provided.
First, we calculate the moles of bromine in the 0.08 g sample:
Moles of bromine = Mass of bromine / Molar mass of bromine
Moles of bromine = 0.08 g / 79.904 g/mol (molar mass of Br)
Moles of bromine ≈ 0.001002 moles
Now, we calculate the molar mass of the compound:
Molar mass of the compound = Mass of the compound / Moles of bromine
Molar mass of the compound = 0.172 g / 0.001002 moles
Molar mass of the compound ≈ 171.656 g/mol
Next, we compare the molar mass obtained with the molar masses of the compounds provided in the options:
- (a) CH₃CH₂Br: Molar mass ≈ 108.96 g/mol
- (b) CH₂Br₂: Molar mass ≈ 173.83 g/mol
- (c) CHBr₃: Molar mass ≈ 252.73 g/mol
- (d) CBr₄: Molar mass ≈ 331.63 g/mol